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x^2-24x+0.1=0
a = 1; b = -24; c = +0.1;
Δ = b2-4ac
Δ = -242-4·1·0.1
Δ = 575.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-\sqrt{575.6}}{2*1}=\frac{24-\sqrt{575.6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+\sqrt{575.6}}{2*1}=\frac{24+\sqrt{575.6}}{2} $
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